FizzBuzz

A classic programming challenge that tests your understanding of loops and conditions.

Difficulty

⭐ Beginner

Problem Description

Write a program that prints the numbers from 1 to 100. But:

• For multiples of 3, print "Fizz" instead of the number
• For multiples of 5, print "Buzz" instead of the number
• For numbers that are multiples of both 3 and 5, print "FizzBuzz"

Example Output

1
2
Fizz
4
Buzz
Fizz
7
8
Fizz
Buzz
11
Fizz
13
14
FizzBuzz
16
...

Skills Practised

• Loops (for loop)
• Conditional statements (if-else)
• Modulus operator (%)
• Logical operators (&&)

Test Cases

Your solution should produce:

• "Fizz" for: 3, 6, 9, 12, 18, 21, ...
• "Buzz" for: 5, 10, 20, 25, 35, ...
• "FizzBuzz" for: 15, 30, 45, 60, 75, 90
• The number itself for all other cases

Hints

Hint 1: Checking for multiples

Use the modulus operator % to check if a number is divisible by another:

if (number % 3 == 0) {
    // number is divisible by 3
}

Hint 2: Order matters

Check for multiples of both 3 and 5 first, before checking for just 3 or just 5:

if (number % 3 == 0 && number % 5 == 0) {
    // Multiple of both
} else if (number % 3 == 0) {
    // Multiple of 3 only
}

Hint 3: Alternative approach

Instead of checking for both, you could check if a number is divisible by 15:

if (number % 15 == 0) {
    System.out.println("FizzBuzz");
}

Starter Code

public class FizzBuzz {
    public static void main(String[] args) {
        // Write your code here
        for (int i = 1; i <= 100; i++) {
            // Your logic here
        }
    }
}

Solution

Click to reveal solution

public class FizzBuzz {
    public static void main(String[] args) {
        for (int i = 1; i <= 100; i++) {
            if (i % 3 == 0 && i % 5 == 0) {
                System.out.println("FizzBuzz");
            } else if (i % 3 == 0) {
                System.out.println("Fizz");
            } else if (i % 5 == 0) {
                System.out.println("Buzz");
            } else {
                System.out.println(i);
            }
        }
    }
}

Alternative Solution (using method):

public class FizzBuzz {
    public static void main(String[] args) {
        for (int i = 1; i <= 100; i++) {
            System.out.println(fizzBuzz(i));
        }
    }

    public static String fizzBuzz(int number) {
        if (number % 15 == 0) {
            return "FizzBuzz";
        } else if (number % 3 == 0) {
            return "Fizz";
        } else if (number % 5 == 0) {
            return "Buzz";
        } else {
            return String.valueOf(number);
        }
    }
}

Even Cleaner Solution:

public class FizzBuzz {
    public static void main(String[] args) {
        for (int i = 1; i <= 100; i++) {
            String output = "";

            if (i % 3 == 0) output += "Fizz";
            if (i % 5 == 0) output += "Buzz";
            if (output.isEmpty()) output = String.valueOf(i);

            System.out.println(output);
        }
    }
}

Extension Challenges

Once you've completed the basic challenge, try these variations:

1. Custom Range

Modify the program to accept a start and end number as input, rather than always using 1-100.

2. Different Numbers

Change the rules to use different numbers (e.g., 7 and 11 instead of 3 and 5).

3. Three Numbers

Extend FizzBuzz to handle three numbers:

• Multiples of 3: "Fizz"
• Multiples of 5: "Buzz"
• Multiples of 7: "Boom"
• Multiples of 3 and 5: "FizzBuzz"
• Multiples of 3 and 7: "FizzBoom"
• Multiples of 5 and 7: "BuzzBoom"
• Multiples of all three: "FizzBuzzBoom"

4. Method-based Solution

Create a separate method fizzBuzz(int number) that returns a String, then call it in your loop.

What You've Learned

After completing this challenge, you should understand:

• ✅ How to use loops to repeat operations
• ✅ How to check if numbers are divisible using modulus
• ✅ How to use conditional logic to make decisions
• ✅ The importance of condition ordering
• ✅ How to combine multiple conditions with logical operators

Next Challenge

Try the Palindrome Checker challenge next to practise working with strings!